x^2+4x+1=6x2+4x+1=6

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Solution for x^2+4x+1=6x2+4x+1=6 equation: 



x^2+4x+1=6x^2+4x+1=6

We move all terms to the left:

x^2+4x+1-(6x^2+4x+1)=0

We get rid of parentheses

x^2-6x^2+4x-4x-1+1=0

We add all the numbers together, and all the variables

-5x^2=0

a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-10}=0$

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